What Is the Average Volume Gained Each Day for a Newborn?

  • Thread starter Thread starter frog210293
  • Start date Start date
  • Tags Tags
    Average Volume
AI Thread Summary
The discussion focuses on calculating the average volume gained each day for a newborn based on a birth mass of 3.3 kg and a daily weight gain of 1.2 × 10^-2 kg. The initial calculation using the formula V = m/d resulted in an incorrect volume of 1.76 × 10^-5 m³/d. After re-evaluating, a revised calculation yielded 1.18 × 10^-5 m³/d, but this was also deemed incorrect. Participants suggest considering unit conversions to liters or cubic centimeters and emphasize the importance of significant figures in the calculations. The conversation highlights the need for accuracy in both calculations and unit representation.
frog210293
Messages
12
Reaction score
0

Homework Statement



If the child's birth mass is 3.3 kg, birth rate =1.2×10−2 kg/d (baby gains that amount each day) A child is born after 39 weeks in its mother's womb.
Assuming the fetal density is 1020 kg/m^3, what is the average volume gained each day?

Homework Equations





The Attempt at a Solution



V=m/d
V=(1.2*10^-2)/1020
V=1.76*10^-5 which is incorrect??
 
Physics news on Phys.org
Hell frog210293,

Welcome to Physics Forums!
frog210293 said:
V=(1.2*10^-2)/1020
V=1.76*10^-5 which is incorrect??
Redo your calculation. (1.2 x 10-2 [kg d-1])/(1020 [kg1 m-3]) ≠ 1.76 x 10-5 [m3 d-1].
 
ohh woops i redid it with the brackets and came up with 1.18*10^-5 but this is still wrong?
 
frog210293 said:
ohh woops i redid it with the brackets and came up with 1.18*10^-5 but this is still wrong?
That's about the answer that I got.

Are you supposed to give your answer in m3 per day, or do you need to convert to some other units like liters per day (or cubic centimeters per day)?

Also, there are two ways to do the problem. You could trust the given mass rate of 1.2 × 10−2 kg/d, or you could recalculate a more precise version given that the birth mass was 3.3 kg, and the time elapsed was 39 weeks. (You get almost the same rate of 1.2 × 10−2 kg/d, but with more significant figures.)

Maybe the program is counting it wrong because you are not using the correct number of significant digits, maybe? I'm not sure.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top