What Is the Best Method to Integrate dx/(x*sqrt(9+16x^2))?

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Homework Help Overview

The discussion revolves around the indefinite integral of the function dx/(x*sqrt(9+16x^2)), which falls under the subject area of calculus, specifically integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use integration by parts but finds it complicated. They also consider trigonometric substitution but express uncertainty about how to proceed. Some participants suggest rewriting the integral and using a substitution involving the expression under the square root.

Discussion Status

Participants are exploring different methods to approach the integral, with some offering specific substitutions and transformations. There is a mix of ideas being shared, but no consensus has been reached on a single method.

Contextual Notes

There is mention of potential constraints regarding the complexity of the integral and the original poster's struggle with the problem setup. Additionally, some participants reference external resources for further assistance.

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Homework Statement




indefinite integral: dx/(x*sqrt(9+16x^2))


Homework Equations



Trig. Substitutions or parts??

The Attempt at a Solution



I tried using integration by parts but its got pretty messy...it also resembles a tan trig substitution, but it's within a square root. I'm stumped and can't figure out where to start...

Can anyone help?

Thanks!
 
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Don't use integration by parts. Rewrite the problem as
\int\frac{xdx}{x^2\sqrt{9+ 16x^2}}
and let u= 9+ 16x^2.
 
Last edited by a moderator:
Factor a 3 out of \sqrt{9 +16x^2}

\displaystyle \sqrt{9 +16x^2}=\sqrt{9\left(1+\frac{16x^2}{9}\right)}=3 \sqrt{1+\frac{16x^2}{9}}=3 \sqrt{1+\left( \frac{4x}{3} \right)^2 }

We know that 1+tan2(θ) = sec2(θ) , so let 4x/3 = tan(θ), (4/3)dx = sec2(θ)dθ.

(I'm slow at typing, so HallsofIvy responded while I was typing. He usually has better ideas than I do. Good luck!)
 
Last edited:

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