What is the best way to reduce radiation exposure in a hospital laboratory?

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1. Homework Statement

a gamma raidiation source (226Ra) is used in hospital laboratory. if shielding is considered as a means of control how many centimeters are needed to reduce the radiation to 1% of what a worker would be exposed to without shielding? assume the shield material is a) concrete B)lead C) steel note the half thicknesses are 0.12m, 0.014m ,0.018m respectively

part 2
as an alternative to shielding of the radiation source in the above question is to extend the distance between the radiation and the worker if the initial design placed the worker at 1m and then the design was review and place the source 10m what percentage reduction in radiation exposure would there for the second position relative to the first

2. Homework Equations

part 1 n=-2/log1/2
part 1 df/di = (ri/rf)^2 ri=1m rf=10m
3. The Attempt at a Solution

i have no idea how to do ether i asked the lecturer and he said there was a way without have to do logarithms for the first part but didn't explain how and i need to know how for my exams please and help is greatly appreciated!
 
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Hey, i have a similar problem and the best I've come up with so far is the inverse square law, ie at 1m dose rate constant, at 2m the dose rate is the square of the distance thus at 3m equals 9m2 etc then the HVL of the shielding material is calculated by thickness required to absorb half of the remaining dose.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.

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