Kashuno
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Homework Statement
"A capacitor is being charged from a battery and through a resistor of 20kΩ. It is observed that the voltage on the capacitor rises from 10% of its final value to 90%, in 15 seconds. Calculate the capacitor's capacitance.
t = 15s
R = 20kΩ
Vi = 10% of max
Vf = 90% of max
Homework Equations
Vc(t) = Vs(1-e^(-t/τ))
τ = RC
The Attempt at a Solution
Vc(t) = 90% = .9
Vs = 100% = 1.0
.9 = 1.0(1-e^(-t/τ))
.9 = 1-e^(-t/τ)
e^(-t/τ) = .1
From there it has been a while since I took calculus, but I continued with
ln(e^-t/τ) = ln(.1)
-t/τ = ln(.1)
-15/20000C = ln(.1)
-.00075 = ln(.1)C
C = .000326 F
I got an answer, but I feel like I am missing something to do with the voltage on the capacitor at t = 0 being 10%. I have no way to check if this answer is correct, so I guess I'm really just asking for someone to check my work (and if it's wrong, give me a push in the right direction)
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