What is the capacitance of the circuit problem.

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SUMMARY

The capacitance of an LC circuit with a 1mH inductor, where the energy in the capacitor is halved after 2.1 ms, is calculated to be 4.4 microfarads. The solution utilizes Thomson's formula, T = 2π√(LC), to determine the full period of discharge, which is 4.2 ms. The charge variation is modeled by the equation Q = QoCos(wt), where w represents the angular frequency. The relationship between time and energy discharge is critical for solving this problem.

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Homework Statement


An LC circuit consists of a 1mH inductor. The capacitor is fully charged. After 2.1 ms,
the energy in the capacitor is ½ of its original value. What is the capacitance of the
circuit?


Homework Equations


(Q/C)+ L(d^2Q/dt^2)=0

d^2Q/dt^2= -(1/LC)Q


The Attempt at a Solution



I found the above equations in my physics book but I don't know what Q would be (it says that the capacitor is fully charged but it doesn't give an actual number), or how to get into a C= ? format in order to find the capacitance. Also I'm not even sure these are the formulas I need for this problem and if they're not then I have no idea what to do.
 
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you can try to solve the task using Thomson's formula T=2*П * root of L*C
as i understood there is given that after 2,1 ms the capacitor is half discharged and it means that it will be fully dischardged after 4,2 ms, that is 4,2*10^-3 s - it is full period of time.
transforming the formula C= (T^2) / (2^2 * П^2 * L) and the result is 4,4 micro farads.
 


The charge varies with time according to a cosine function - Q=QoCos(wt)
w is the angular frequency.
From the fact that is 1/2 from the maximum at t=2.1 ms you can find w.
 

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