What is the cause of the pull on the charged metal plate?

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The discussion centers on calculating the outward pull on a charged circular metal plate with a radius of 10 cm and a charge of 20 microCoulombs. The formula for force, F = [sigma^2]A / (2 epsilon * K), is used, where sigma is the surface charge density calculated as Q/A. There is a debate about whether to use the area of one surface (pi * r^2) or both surfaces (2 * pi * r^2) for the calculation. Additionally, participants emphasize that for the plate to experience a pull, it must be in an electric field or part of a larger conductor with a uniform charge distribution. Understanding the electric field's role is crucial for explaining the force experienced by the plate.
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1. A circular metal plate of radius 10cm is given a charge of 20 microCoulomb. Determine the outward pull on the plate, k=1

i can solve the problem by using the equation F= [sigma ^2]A / 2 epsilon* K and finding \sigma = Q/A {where A= area of surface(plate), Q = charge}

My problem:
to find area of plate i used the equation pi *r^2; or do i need to consider 2\pir^2 as plate have two surfaces.
 
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sphyics said:
1. A circular metal plate of radius 10cm is given a charge of 20 microCoulomb. Determine the outward pull on the plate, k=1

i can solve the problem by using the equation F= [sigma ^2]A / 2 epsilon* K and finding \sigma = Q/A {where A= area of surface(plate), Q = charge}

My problem:
to find area of plate i used the equation pi *r^2; or do i need to consider 2\pir^2 as plate have two surfaces.

I want to help you, but I'm stuck as to understand why there is a pull on the plate. Is it situated in an electric field?
 
fluidistic said:
I want to help you, but I'm stuck as to understand why there is a pull on the plate. Is it situated in an electric field?

i havn't thought that way, ofcourse what i feel is u r right :) inoder to experience a pull there must be presence of electric field, i.e it must be placed in an electric field. or it must experience an electric field. like if the part under consideration is a part of larger conductor and the charges are spread uniformly, throught the larger one, then smaller part of that conductor will experience a force.
 
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