What is the Centripetal Acceleration of an Earth Satellite in a Circular Orbit?

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To calculate the centripetal acceleration of an Earth satellite in a circular orbit at a radius four times that of Earth, the gravitational force formula F=Gm1m2/d^2 is referenced. The satellite's acceleration can be determined by recognizing that gravitational force decreases with the square of the distance, making it 16 times weaker at this distance. The ratio of the satellite's orbit to Earth's radius is sufficient for solving the problem without needing specific mass values. Additionally, centripetal acceleration can be calculated using the orbital speed squared divided by the radius of the orbit. Understanding these principles allows for the determination of the satellite's acceleration in m/s^2.
thomasrules
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i don't know what formula to use... I know that F=Gm1m2/d^2

An Earth satellite travels in a circular orbit of radius four times the Earth's radius. Calculate its acceleration in m/s^2.
 
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You can solve it by looking at the acceleration due to gravity on the Earth's surface and the ratio between Core to Surface :: Core to Satellite orbit. Since F is inversely proportional to distance^2, it should be 16 times weaker.
 
hm,mmmmmmm
 
how do i find the distance from core to satelite
 
The problem says it's 4 times more than the Earth's radius...

Daniel.
 
You are told in the question that it was 4 times the Earth's radius. You don't need the actual figures. The ratio 4:1 is enough to solve the question. But you might also try using that formula to calculate the force on the satellite. But you can't use it if you don't have the mass of the satellite. And from what you said in ur first post, i deduce that ur not given that.

PS. heh he beat me. I type too much. :biggrin:
 
Well, isn't it just the centripetal acceleration of the satellite??
Because then you can take the orbital speed and square it then divide it by 4r?
 
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