What is the Chain Rule for Derivatives?

thomasrules
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Given: h=f\circ g , g(2)=5, g\prime(2)=3, and f\prime(5)=-2
Determine h\prime(2)
 
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Use the fact that (f o g) ' (x) = f ' (g(x)) * g ' (x).
 
i don't get it
 
It's right in front of you, think about it.
 
The Chain rule states that given f(g(x)), the derivative f ' (g(x)) can be found by finding the derivative of f at g(x) multiplied by the derivative of g(x). Which is what radou pointed out.

Do we know f ' (g(x))? Think about what g(x) equals in this case. Do we know g ' (x)? Think! The chain rule is very important!
 
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got it ty...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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