What is the Chain Rule for Differentiating ln ln ln x^3?

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To differentiate the function ln ln ln x^3, the chain rule is applied. First, let t = ln x^3, then y = ln ln t, and u = ln t. The derivative is calculated as dy/dx = (dy/du) * (du/dt) * (dt/dx). The final result simplifies to 1/ln ln x^3, confirming the teacher's answer.
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Homework Statement


ln ln ln x^3


Homework Equations





The Attempt at a Solution


My teacher was going over the review for the final and this was one of the questions. He said the answer is 1/ln ln x^3 but I don't know how to get that...can someone please help me...thank you!
 
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y=ln ln ln x^3

Let t= lnx^3

so you have y= ln lnt

Let u=lnt

so you have y=lnu

by the chain rule

\frac{dy}{dx}=\frac{dy}{du}*\frac{du}{dt}*\frac{dt}{dx}
 
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