What is the Chain Rule for Differentiating tan^3(x) + tan(x^3)?

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Homework Statement



tan^3(x) + tan(x^3)

Homework Equations





The Attempt at a Solution



tan^3(x) + sec^2(x^3) + 3x^2


Im not sure how to do the tan^3(x) and not even sure I did the tan(x^3) right
 
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the first term is as follows
\frac{d}{dx} (tan(x))^3 = 3 tan^2(x)\frac{d (tan(x))}{dx} =..

here assume you have
g(x) = x^3
f(x) = tan(x)

and you know
g(x) = 3x^2
f(x) = sec(x)

in this form it becomes
g(f(x)) = (tan(x))^3 =..

\frac{d}{dx} g(f(x)) = g'(f(x))f'(x) = ...

finish this & try the 2nd term again as its not correct either
 
expanded above
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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