What is the Charge of Two Suspended Pith Balls at Equilibrium?

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The discussion revolves around calculating the electric force and charge of two suspended pith balls in equilibrium, each with a mass of 4.9 g and equal charge. The suspended ball forms a 30° angle with the vertical when another ball is brought close, creating a scenario involving gravitational force, tension, and electric force. Participants suggest using the formula Fe=(K(qa)(qb))/r^2 to find the electric force, but emphasize that the charges must first be determined from the force diagram. The tension can be calculated using the known weight and angle, allowing for the determination of the electric force. Ultimately, the charge can be solved for, noting that while the exact sign of the charge is unknown, they are confirmed to repel each other.
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Homework Statement


The two pith balls below each have a mass of 4.9 g and equal charge. One pith ball is suspended by an insulating thread. The other is brought to x = 3.5 cm from the suspended ball. The suspended ball is now hanging with the thread forming an angle of 30.0° with the vertical. The ball is in equilibrium with FE, Fg, and FT. Calculate each of the following.

Fg (got that)

Fe (Havent gotten that)

Charge (Have no real clue how to get that)

Homework Equations


Fe=(K(qa)(qb))/r^2


The Attempt at a Solution


I'm assuming I'd be able to use Fe=(K(qa)(qb))/r^2 except I don't know how to find the charges.

Also, as an unrelated question, how do I find Voltage with the electric field and distance in a parallel plate?
 
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Welcome to PF.

Note that the charges are equal. Though there is no indication that they are + or -.

To determine the charge you need to determine the |Fe| from your force diagram. You know the weight and the angle the string is at, so you can figure the Tension and the Fe.

Then solve for |q|, because you don't know the sign of the charge - only that they repel.
 

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