What is the Charge Transfer Process between Two Charged Balls in Electrostatics?

AI Thread Summary
The discussion focuses on the charge transfer process between two charged balls in electrostatics, specifically how ball 1 transfers part of its charge Q to neutral ball 2, which acquires charge q. The conservation of charge principle is applied, leading to the equation Q = Q' + q. The solution involves calculating the capacitance of both balls and equating their potentials to find the ratio of their capacitances. The final charge on ball 2 after repeated contact is expressed as qQ/(Q-q). The process continues until both balls reach the same electric potential.
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Homework Statement


The ball 1 can be charged to a certain charge Q by a generator. After that, through contact with the ball 2, the first ball can transfer to second ball part of its charge. After the first contact, the ball 2 has a charge q. Before the contact, the ball 2 was neutral. What charge the ball 2 can acquire repeating the process repeatedly.

http://www.luiseduardo.com.br/electricity/electrostatics/electrostaticsproblems_arquivos/image002.jpg


Homework Equations


Q = Q'+q --> Conservation of Charges
Q = C.V ---> Capacitor charge
C = r/K ----> Capacitance of a sphere


The Attempt at a Solution



Well, first, I tried to use the conservation of charges equation several times replacing Q' (charge of the sphere that will be recharged) by C.V, where C is the capacitance and V the potential. After that, I didn't find a way to find the answer of the problem. Could anyone help me? Please give me your complete explanation or solution.

PS: The answer of the problem is qQ/(Q-q)

Thanks.
 
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The charge from one ball to another ball will flow till they are at the same potential.
Now, to give you a start, let me tell you the first step:

Assume C1 and C2 as the capacitances of ball 1 and ball2 respectively, equate the potential and find the ratio of \frac{C1}{C2}. Now equate the potential for the 2nd step till you find a relation between the charges transferred.

P.S: 1) The charges will be a part of a series. it is for you to guess which one.
2) It is against the rule of this forum to give a detailed solution. Moreover, I think you should try
your fullest before you look for the solution.

Best of luck!

ADI.
 
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