What is the connection between X_n and Y_n?

Ted123
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Homework Statement



[PLAIN]http://img263.imageshack.us/img263/8679/statsji.jpg

The Attempt at a Solution



I've done part (a) and I know what the CLT says but how does part (a) link with part (b) as if X_n \sim Bern(p) then \displaystyle \sum^n_{i=1} X_i \sim Bin(n,p) so X_n = \displaystyle \sum^n_{i=1} Y_i where Y_1 , \cdots , Y_n \sim Bin(n,p) are i.i.d

BUT X_n \sim Bin(n,p) so where do I go from here?
 
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How did you come up with

X_n = \sum^n_{i=1} Y_i

?
 
vela said:
How did you come up with

X_n = \sum^n_{i=1} Y_i

?

Actually it should be Y_n = \sum^n_{i=1} X_i where X_1, ..., X_n \sim Bern(p) (iid)

so \frac{Y_n - \mathbb{E}[Y_n]}{\sqrt{Var(Y_n)}} = \frac{Y_n - \sum^n_{i=1} \mathbb{E}[Y_i]}{\sqrt{\sum^n_{i=1} Var(Y_i)}} = \frac{Y_n - n\mathbb{E}[Y_1]}{\sqrt{nVar(Y_1)}} = \frac{Y_n - np}{\sqrt{np(1-p)}} \to Y ;\; Y\sim N(0,1) by CLT
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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