What is the correct A value for normalizing the given wave function?

[Gregg]

Homework Statement

The function

\Psi(r) = A(2-{Zr\over a})e^-{Zr\over 2a}

gives the form of the quantum mechanical wavefunction representing the electron
in a hydrogen-like atom of atomic number Z when the electron is in its first
allowed spherically symmetric excited state. Here r is the usual spherical polar
coordinate, but, because of the spherical symmetry, the coordinates θ and φ do
not appear explicitly in Ψ. Determine the value that A (assumed real) must have
if the wavefunction is to be correctly normalised, i.e. the volume integral of |Ψ|^2
over all space is equal to unity.

The Attempt at a Solution

{\int \int \int}_R |\Psi|^2 dV = 1

\int _0^{\infty }\int _0^{2\pi }\int _0^{\pi }A^2e^{-\frac{Zr}{a}} \left(2-\frac{Zr}{a}\right)^2d\phi d\theta dr = 1

Which implies

\int _0^{\infty }A^2e^{-\frac{\text{Zr}}{a}} \left(2-\frac{\text{Zr}}{a}\right)^2dr = {1\over 2\pi^2}

This turns out to be

\frac{2aA^2}{Z} = \frac{1}{2\pi^2}

A = \pm \frac{\sqrt{\frac{z}{a}}}{2\pi}

This is wrong though?
Is the problem the fact that Psi(r) isn't a function of theta or phi?

 

[Päällikkö]

Looks to me you forgot the r² sin term from the differential volume element (note that the way you did it, the volume of a unit ball would come out as 2pi²). See http://en.wikipedia.org/wiki/Spherical_coordinate_system