What Is the Correct Formula for Normal Force on a Sloped Surface?

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To calculate the normal force exerted by the skis on a slope, the correct formula is F = m * g * cos(θ), where θ is the angle of the slope. For a skier with a mass of 51.4 kg on a slope of 26 degrees, the normal force can be determined using this equation, with g being 9.8 m/s². The discussion clarifies that the normal force is not related to the sine of the angle, as that would not yield a valid result for a slope approaching 0 degrees. Therefore, the normal force is directly linked to the cosine of the slope angle. Understanding the relationship between the angle and the forces involved is crucial for solving problems related to inclined planes.
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1. A skier of mass 51.4 kg comes down a slope of constant angle 26◦ with the horizontal. What force normal to the slope is exerted by the skis (neglect friction)? The acceleration of gravity is 9.8 m/s^2.



Homework Equations



F=ma

The Attempt at a Solution



my intuitions tell me to do this:

F=m*g*cos26

am i wrong?
 
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Robertoalva said:
1. A skier of mass 51.4 kg comes down a slope of constant angle 26◦ with the horizontal. What force normal to the slope is exerted by the skis (neglect friction)? The acceleration of gravity is 9.8 m/s^2.



Homework Equations



F=ma

The Attempt at a Solution



my intuitions tell me to do this:

F=m*g*cos26

am i wrong?

A hint on how to think:

The answer is either m*g*cos26 or m*g*sin26

Suppose the slope was ≈ 0 degrees; one of m*g*cos0 or m*g*sin0 is zero.

If the slope was ≈ 0 degrees, would the normal force be ≈ 0 ?

That shows which one is NOT the answer.
 
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