What is the derivative of the integral of x^2t^2 from 0 to x?

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SUMMARY

The derivative of the integral of the function \(x^2 t^2\) from 0 to \(x\) is computed using the Leibniz Integral Rule. The correct approach involves recognizing that \(x^2\) acts as a constant multiplier, allowing it to be factored out of the integral. The solution simplifies to \(d/dx (\int^{x}_{0} x^2 t^2 dt) = \frac{5}{3} x^4\), confirming the derivative is correctly calculated as \(5/3 x^4\). This method is essential for handling integrals where the variable appears both in the integrand and as an upper limit.

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Homework Statement



d/dx (\int^{x}_{0} x2t2dt)
So the problem is to solve the derivative of the integral \int x2t2dt from 0 to x.

Homework Equations



d/dx (\int^{x}_{a} f(t)dt) = f(x)

The Attempt at a Solution



I'm really unsure of how this should be computed but this was my guess:

d/dx (\int^{x}_{0} x2t2dt) = d/dx (1/3x2(x)3 -(1/3x2(0)3)) = d/dx (1/3x5) = 5/3x4

So, first I calculated the integral with respect to t and then derivated it with respect to x. But it feels wrong. I don't know how to treat the function x2t2 because the variable x is both part of the function and an endpoint of the interval for integration.
 
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You don't have to treat x^2 as 'part of the function'. It's just a constant multiplying the function t^2. You can take it out of the integral. If you have to do more complicated problems where the x and t are mixed up so you can't do that, check out the Leibniz Integral Rule. So your answer is correct.
 

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