What Is the Difference Between H Field and B Field in a Solenoid?

anon6912
Messages
21
Reaction score
3
This is a slide from my lecture illustrating how to find the magnetic field in a solonoid with an air gap.

I don't quite understand the following points:
What is the H field?
Whats the difference between the H field and the B field?
Why do you need them?

Other than that i understand how to do the integral and the evaluation. I just don't understand what the H field is.

EDIT: I attached a nother slide about the H field
 

Attachments

  • HB field.JPG
    HB field.JPG
    34 KB · Views: 452
  • HB field 2.JPG
    HB field 2.JPG
    27.1 KB · Views: 453
Physics news on Phys.org
H is the magnetic field strength while B is the flux density. The strict definition of H is

H = B / μ0 - M where M is the magnetisation

However it is usually possible to simplify the calculation

H = B / μ

look at http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magfield.html or search for "magnetic field strength H" and you will most likely find what you need
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top