What is the difference between linear and homogeneous systems of equations?

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Homework Statement



I've been struggling for the past hours and can't find the difference between "linear system of algebric equation " and "homogenus system of equation" ,I have the oral(writting) exam tuesday and I would appreciate a little help since I passed writting exam and only final oral would grant me passage to next semester so Id get rid of so many months of suffering .Thanks all
 
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The word 'homogeneous' entails that all constant terms are zero, which is not required for an algebraic equation.
 
In a linear system of equations, the variables all occur to the first power, as in this example

x + 2y + 3z = 4
-x + 3y -z = 8

I'm not sure what the "algebraic" part contributes.

In a homogeneous system of equations, all the variables are on one side of each equation and the constants on the right side are all zero, as in

x + 2y + 3z = 0
-x + 3y -z = 0

Now, since it wasn't specified that these are linear equations, we could have systems like this

x2 + 2sin(y) + 3z1/2 = 0
-x + 3cos(y) - 1/z = 0

This is a homogeneous system of nonlinear equations.

Hope that helps.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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