What is the difference between linear and homogeneous systems of equations?

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Homework Statement



I've been struggling for the past hours and can't find the difference between "linear system of algebric equation " and "homogenus system of equation" ,I have the oral(writting) exam tuesday and I would appreciate a little help since I passed writting exam and only final oral would grant me passage to next semester so Id get rid of so many months of suffering .Thanks all
 
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The word 'homogeneous' entails that all constant terms are zero, which is not required for an algebraic equation.
 
In a linear system of equations, the variables all occur to the first power, as in this example

x + 2y + 3z = 4
-x + 3y -z = 8

I'm not sure what the "algebraic" part contributes.

In a homogeneous system of equations, all the variables are on one side of each equation and the constants on the right side are all zero, as in

x + 2y + 3z = 0
-x + 3y -z = 0

Now, since it wasn't specified that these are linear equations, we could have systems like this

x2 + 2sin(y) + 3z1/2 = 0
-x + 3cos(y) - 1/z = 0

This is a homogeneous system of nonlinear equations.

Hope that helps.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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