What is the effective spring constant of a charged DNA molecule?

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The discussion revolves around calculating the effective spring constant of a charged DNA molecule, which is 2.10 μm long and compresses by 1.09% when ionized. The user attempts to apply Coulomb's law and Hooke's law to find the spring constant but receives feedback indicating their answer is incorrect, albeit within 10% of the correct value. A key point raised is that the distance used in Coulomb's law should account for the compression of the DNA molecule, suggesting it should be slightly less than 2.10 μm. This adjustment is crucial for accurately determining the effective spring constant. The conversation highlights the importance of considering physical changes in the system when applying theoretical equations.
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Homework Statement


A molecule of DNA (deoxyribonucleic acid) is 2.10 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.09% upon becoming charged. Determine the effective spring constant of the molecule.

Homework Equations



Q = 1.9 E-19

F = KQ^2/r^2

F= kx

The Attempt at a Solution



F = KQ^2/r^2

F = ((8.99E9)*(1.6E-19)^2)/(2.1E-6)^2

F = 5.224489796E-17 N

F = kx

k = (5.224489796E-17)/(0.0109*2.1E-6)

k = 2.282433288E-9 N/m

This is the answer I get but the software keeps saying my answer is wrong BUT within 10% of the correct answer. I've done it about 10 times now and don't understand. Can anybody see anything wrong?
 
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jybe said:

Homework Statement


A molecule of DNA (deoxyribonucleic acid) is 2.10 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.09% upon becoming charged. Determine the effective spring constant of the molecule.

Homework Equations



Q = 1.9 E-19

F = KQ^2/r^2

F= kx

The Attempt at a Solution



F = KQ^2/r^2

F = ((8.99E9)*(1.6E-19)^2)/(2.1E-6)^2

F = 5.224489796E-17 N

F = kx

k = (5.224489796E-17)/(0.0109*2.1E-6)

k = 2.282433288E-9 N/m

This is the answer I get but the software keeps saying my answer is wrong BUT within 10% of the correct answer. I've done it about 10 times now and don't understand. Can anybody see anything wrong?
Almost good.

When you use Coulomb's law to get the force, the distance between charges is reduced to slightly less than 2.10 μm. Right?
 
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