What is the Electric Field inside this charged sphere?

  • Thread starter k_squared
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Homework Statement


Let me just put this here:
http://i.imgur.com/dgcWAC3.png
dgcWAC3.png

.

Homework Equations


E_flux=EA=(q_encl)/(permittivity)
Area=4pir^2

The Attempt at a Solution


Whenever I manipulate the above equations, I get a term of the form R/r, which implies, R being 5 cm, and r being the radius inside. This implies that the field goes to infinity at the center, when I'm pretty sure by spherical symmetry it is 0!
 

Answers and Replies

  • #2
Doc Al
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Whenever I manipulate the above equations, I get a term of the form R/r, which implies, R being 5 cm, and r being the radius inside.
Not sure how you'd get an expression with R = 5 cm, when evaluating the field at r = 4 cm. Using Gauss' law at r = 4 cm gives you the field at that point, assuming spherical symmetry. What's the enclosed charge at that radius?

when I'm pretty sure by spherical symmetry it is 0!
That's true and Gauss' law agrees.
 

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