Not sure how you'd get an expression with R = 5 cm, when evaluating the field at r = 4 cm. Using Gauss' law at r = 4 cm gives you the field at that point, assuming spherical symmetry. What's the enclosed charge at that radius?k_squared said:
That's true and Gauss' law agrees.k_squared said:
An electric field is a physical quantity that describes the influence of an electric charge on other charges in the surrounding space. It is a vector quantity, meaning it has both magnitude and direction.
The electric field inside a charged sphere is calculated using the formula E = Q / (4πε0r2), where Q is the charge of the sphere, ε0 is the permittivity of free space, and r is the distance from the center of the sphere.
Yes, the electric field inside a charged sphere is uniform. This means that the magnitude and direction of the electric field are the same at all points inside the sphere.
The electric field inside a charged sphere varies inversely with the square of the distance from the center. This means that as the distance from the center increases, the electric field decreases.
Yes, the electric field inside a charged sphere can be negative. This would occur if the charge of the sphere is negative, causing the direction of the electric field to be inward towards the center of the sphere.