What Is the Energy in a Wave and How Does It Change with Different Openings?

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The discussion centers on understanding the energy in a wave, specifically sound waves, and how it relates to intensity and area. Intensity, measured in watts per square meter, indicates how energy spreads over a surface area as sound waves propagate. As the distance from a sound source increases, the energy is distributed over a larger area, resulting in lower intensity at greater distances. The size of the listening device affects the amount of energy it intercepts; larger devices capture more energy due to their increased surface area. Overall, the energy in a wave changes with different openings primarily due to the distribution of intensity over varying surface areas.
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i just learned this so don't be shy about telling me i have no idea what I am talking about;

anyway if you have a wave, say sound, you can find the intensity of the wave, say I

now I is in watts/meters^2 so in the example of sound you can find the amount of energy that the wave makes(?), has(?) by multiplying by the area that the wave goes through (for example a window)

my question is what exactly is the "energy in a wave", and can someone exaplain why the wave can have different "energies" by going through larger openenings(?)

also I am not even sure if there is such a thing as the "energy of wave" so
 
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The measure of intensity -- watts per square meter -- has nothing to do with openings.

The watt is a unit of power. Power is effectively the movement of energy; one watt is defined as one joule moved per second. The joule is a unit of energy.

A simple spherical source produces spherically symmetric waves which spread out from it. If you're close to the source, the sound is very loud; if you're far away, the sound is quieter. If the source radiates a constant amount of energy in the form of sound every second -- say, it generates one joule of sound energy per second (that's one watt) -- that energy will be spread over the entire sphere surrounding it.

A sphere, of course, has a surface area. If you place a listening device one meter away from your one-watt sound source, you can imagine it on the surface of a 1-meter radius sphere surrounding the source. The sound energy is spread over the entire surface area of that sphere, which has a surface area of almost 13 square meters. Thus, the sound intensity at a distance of one meter is one watt spread over 13 square meters, or about 1/13 watt per square meter.

If you place the listening device 10 meters away instead, the sphere surrounding the source is now 10 meters in radius, and has a surface area of almost 1300 square meters. The sound intensity there is only one watt spread over 1300 square meters, or about 1/1300 watt per square meter.

If you make your listening device exactly one square meter in size, it will intercept about 1/1300 watts of power when placed 10 meters away from your source. If you make a larger detector, say one that is 10 square meters in size, it will intercept ten times as much of the sound energy.

- Warren
 
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