What is the energy of the electron just before it hits

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The discussion centers on calculating the kinetic energy of a 300 eV electron just before it strikes an upper metal plate after being deflected by a 400 V potential difference. The initial kinetic energy in the x-direction remains 300 eV, while the electron gains an additional 200 eV from the vertical component of the electric field. The confusion arises from the calculation of total energy, with one participant suggesting a resultant energy of 360 eV based on vector addition. However, the correct approach is to simply add the energies, resulting in a total of 500 eV just before impact. The key takeaway is that energy should be summed directly rather than treated as a vector quantity.
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Homework Statement


A 300 eV electron is aimed midway between two parallel metal plates with a potential difference of 400 V. The electron is deflected upwards and strikes the upper plate as shown.
What would be the kinetic energy of the electron just before striking the metal plate?

Homework Equations


Magnitude of the resultant vector =
= Sqrt [ Ex^2 + Ey^2 ] = Sqrt [ (300eV)^2 + (200eV)^2 ] = Sqrt [ (2e2)^2 + (3e2)^2 ] = 360 eV

The Attempt at a Solution


The electron energy in x direction is unaffected by the 400 V field. So it is present just before hitting the plate.
And the electron goes thru half of the 400V = 200 V vertically picking up energy of 200 eV.
So the resultant total energy is the vector sum of the x and y components of 200eV and 300eV.
BUT
The answer sheet say the final energy before striking the plate is 500eV
I do not see why is is not 360eV as calculated above.

Thanks for your help
 
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paulfr said:
So the resultant total energy is the vector sum of the x and y components of 200eV and 300eV.
Energy is not a vector! (Just add them up.)
 
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