donjt81
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20 J is placed across a 15uF capacitor. What is the energy stored in the capacitor?
any ideas on how to do this?
any ideas on how to do this?
The energy stored in a capacitor can be calculated using the formula \( E = \frac{1}{2} C V^2 \). In this discussion, a 15 µF capacitor is charged to 20 volts, resulting in an energy storage of 3 J. The initial confusion regarding 20 J was clarified, as the correct interpretation involves voltage rather than energy directly applied. The integration method discussed involves the relationship between voltage and charge, confirming that energy is stored as the capacitor charges up to 20 V.
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Check the question. I think it should be 20 volts not 20 J. (If 20 J is added to the capacitor, the energy stored in the capacitor is 20 J. because there is no energy is lost due to resistance).donjt81 said:20 J is placed across a 15uF capacitor. What is the energy stored in the capacitor?
any ideas on how to do this?