What is the equation for the line with the same x-intercept as -2x + y = 1?

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SUMMARY

The equation for the line that passes through the point (6, 2) and shares the same x-intercept as the line defined by -2x + y = 1 is derived by first calculating the x-intercept of the given line. The x-intercept is found by setting y to 0, resulting in x = -1/2. The final equation of the desired line, expressed in the form Ax + By + C = 0, is determined to be 2x + y - 10 = 0.

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mathdad
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Find an equation of the line passing through (6, 2) and has the same x-intercept as the line -2x + y = 1. Express final answer in the form Ax + By + C = 0.

How do I find the x-intercept of the given line?

How do I express the final answer in the form given above?
 
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RTCNTC said:
Find an equation of the line passing through (6, 2) and has the same x-intercept as the line -2x + y = 1. Express final answer in the form Ax + By + C = 0.

How do I find the x-intercept of the given line?

How do I express the final answer in the form given above?

x intercept of a line is value of x when y = 0

for -2x + y = 1 we need to compute x when y= 0 we get $-2x = 1$ or $x= \frac{-1}{2}$. this is the x intercept
 
Great. I can take it from here. I suspected that letting y = 0 would yield the needed x-intercept but wanted to be sure.
 

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