What is the equation for torque in a system with two blocks and a pulley?

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The discussion focuses on calculating torque in a system involving two blocks and a pulley. The correct approach involves applying Newton's second law to each block and the pulley, rather than assuming tension equals the weight of the blocks. Torque is relevant only for the pulley, created by the tensions in the ropes on either side. The equations must combine linear and rotational forms, specifically using ΣF = ma for the blocks and ΣTorque = I*alpha for the pulley. Additionally, understanding the moment of inertia for a hollow cylinder is crucial for determining the system's acceleration.
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Homework Statement



http://imgur.com/MaT4N

MaT4N.png



Homework Equations



Torque = Fr

The Attempt at a Solution



1) I tried
m2 g r - m1 g r = 1/2 M r^2 * (acceleration / r)
didn't work

2)I tried replace the moment of inertia equation to above equation,still didn't work
 

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TBBTs said:
1) I tried
m2 g r - m1 g r = 1/2 M r^2 * (acceleration / r)
didn't work
You cannot assume that the tension in the ropes equals the weight of the blocks. If that were true, the masses would be in equilibrium, not accelerating.

Instead, apply Newton's 2nd law to each block and to the pulley. Combine those three equations to solve for the unknowns.
 
Hi!
I tried this m2gR - m1gr +mgR =0

I am confused about which forces has torque on this problem?
How do I suppose to set up with an equation with both torque and Newton's second law?
Thanks!
 
Also,I am still confused about second part. Thanks
 
TBBTs said:
Hi!
I tried this m2gR - m1gr +mgR =0
Not sure what you're doing here.
I am confused about which forces has torque on this problem?
Torque is only relevant for the pulley. The forces creating the torque on the pulley are the rope tensions on each side of the pulley.
How do I suppose to set up with an equation with both torque and Newton's second law?
For the two blocks, you'd use the usual form of Newton's 2nd law: ΣF = ma

But for the pulley, you'll need the rotational form, which uses torque, rotational inertia, and angular acceleration: ΣTorque = I*alpha.

TBBTs said:
Also,I am still confused about second part. Thanks
To solve the second part, you'll need to replace the rotational inertia of the pulley with that of a hollow cylinder. Then you'd have to determine whether that causes the acceleration to increase, decrease, or remain the same. (Hint: How does the rotational inertia of a hollow cylinder compare to that of solid cylinder?)
 
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