What is the equation to solve for v in this problem?

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The discussion focuses on solving the equation \(\frac{150}{v+20}+\frac{150}{v-5}=3.5\). Participants suggest steps to eliminate fractions by finding a common denominator and cross-multiplying. A quadratic equation is derived, leading to the expression \(3.5v^2 + 52.5v - 650\). There is a correction regarding the final form of the equation, indicating that the derived equation does not simplify to the previously mentioned form. The conversation emphasizes the importance of verifying calculations in solving for \(v\).
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can some 1 give me a hand with this? thanks
\frac{150}{v+20}+\frac{150}{v-5}=3.5
 
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1. make the denominator the same.
2. cross multiply the equation to get rid of the fraction form.
3. solve the quadratic equation.
 
i get the -65 n 80 which i think is right so thanks leong
 
check your answer !
 
80 works, -65 doesnt
 
it came down to:
3.5v^2+52.5v-650
 
Uhmmm, I think you should check your calculation again.
Here we go:
\frac{150}{v + 20} + \frac{150}{v - 5} = 3.5
Multiply both sides by (v + 20) (v - 5)
\Leftrightarrow (v + 20)(v - 5)\left(\frac{150}{v + 20} + \frac{150}{v - 5}\right) = 3.5(v + 20)(v - 5)
\Leftrightarrow 150(v - 5) + 150(v + 20) = 3.5(v ^ 2 + 15v - 100)
\Leftrightarrow 300v + 2250 = 3.5v ^ 2 + 52.5v - 350
\Leftrightarrow ...
Can you go from here?
By the way, it does not come down to 3.5v2 + 52.5v - 650 = 0.
Viet Dao,
 
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