What is the Escape Speed of an Electron from a Charged Glass Sphere?

AI Thread Summary
The discussion revolves around calculating the escape speed of an electron from a charged glass sphere with a diameter of 7.42 cm and a charge of 7.04 nC. The relevant equations include the potential energy formula and kinetic energy, leading to the escape speed equation v = √(2kqq/rm). An error in the calculation is identified, suggesting that the charge and diameter values may have been mixed up. The correct approach requires careful attention to the values used for charge and radius. Accurate calculations are essential for determining the correct escape speed.
kmikias
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\sqrt{}

Homework Statement



What is the escape speed (in m/s) of an electron launched from the surface of a 7.42 cm diameter glass sphere that has been charged to 7.04 nC?

Homework Equations



u=kqq/r
KE=1/2MV^2
UO=KE

The Attempt at a Solution


here is what i did
kqq/r = 1/2mv^2
solve for v
v=\sqrt{}2kqq/rm
i used q = 7.42 square
and mass of electron = 9.11*10^-31
and r = 0.0704/2
...but still my answer is wrong
 
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kmikias said:
What is the escape speed (in m/s) of an electron launched from the surface of a 7.42 cm diameter glass sphere that has been charged to 7.04 nC?

kmikias said:

The Attempt at a Solution


here is what i did
kqq/r = 1/2mv^2
solve for v
v=\sqrt{}2kqq/rm
i used q = 7.42 square
and mass of electron = 9.11*10^-31
and r = 0.0704/2
...but still my answer is wrong

I believe you have the value of the sphere's charge, and the diameter of the sphere interchanged.
 
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