What is the explicit representation of 2cos(omega)t - 1/4 sin(omega)t = 0?

[itr]

explicit representation??

I got to show the explicit representation of 2cos(omega)t - 1/4 sin(omega)t = 0. what is this? is this operator notation??

 

[HallsofIvy]

I have no idea what you mean by "explicit repesentation". Obviously 2cos(\omega t)- (1/4)sin(\omega t)= 0 is only true for some values of t.
Specifically, if 2cos(\omega t)- (1/4)sin(\omega t)= 0 , then (1/4)sin(\omega t)= 2 cos(\omega t) and sin(\omega t)/cos(\omega t)= tan(\omega t)= 8. You could use a calculator to see what \omega t must equal.
Where did you see that? What was the context?