What is the final speed of the crate?

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A crate with a mass of 120 kg initially moves at 2.5 m/s before being pushed by an astronaut with a force of 250 N over 7 m, then slowed down by a force of 240 N over 6 m. The net work done on the crate is calculated using the formula W = F1*S1 - F2*S2. The initial kinetic energy (KE) is combined with the net work to find the final kinetic energy. By applying the equation 0.5 M*V2^2 = 0.5*M*V1^2 + (F1*S1 - F2*S2), the final speed of the crate can be determined.
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A crate with a mass of 120 kg glides through a space station with a speed of 2.5 m/s. An astronaut speeds it up by pushing on it from behind with a force of 250 N, continually pushing with this force through a distance of 7 m. The astronaut moves around to the front of the crate and slows the crate down by pushing backwards with a force of 240 N, backing up through a distance of 6 m. After these two maneuvers, what is the speed of the crate?



Homework Equations


W=F1*deltaR+F2*deltaR2+...


The Attempt at a Solution


i can't find out how to get the speed with that? please help??
 
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Final KE = Initial KE + Network done on the crate

Let initial velocity be V1 and final velocity be V2
Let Force exerted from back be F1 and distance S1, and F2 be the force exerted from front for distance S2.

Net work done = F1*S1 - F2*S2 (minus because one is back and other is front)
0.5 M*V2^2 = 0.5*M*V1^2 + (F1*S1- F2*S2)

M, V1, F1, F2, S1, S2 are given. Use the above equation to find the final velocity.
 
thank you!
 
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