What Is the Final State of an Ideal Gas After Temperature and Volume Changes?

AI Thread Summary
The discussion revolves around calculating the final state of an ideal gas after changes in temperature and volume. The initial conditions include 4 moles of gas at 300 K and 10 atm pressure, with a temperature change of -50 K and a volume increase of 10 liters. The initial volume was incorrectly calculated due to the wrong gas constant being used; the correct constant is R = 0.08206 L.atm/K.mol. Participants emphasize the importance of using consistent units in calculations to avoid errors. The final temperature, volume, and pressure need to be accurately derived based on these corrections.
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Homework Statement


A moster of a gas has 4 moles and first is in the temperature 300 K and pressure 10 atmosphere.After a change of state, ∆T= -50 K and ∆V=10 liter.Find the final temperature ,volume and pressure of the gas.


Homework Equations



P*v=n*R*T

The Attempt at a Solution


So T2-T1=-50 <=> T2=350-50=300 K
Now,to find V2, I thought : Find V1 first and then do V2-V1=∆V. From pv=nRT where T =300,pressure is 10 and the moles are 4. I Find that V1=997.2 here I replace V2-997.2=10 but V2 isn't the same as in my textbook..what did I do wrong
 
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Elaia06 said:
So T2-T1=-50 <=> T2=350-50=300 K
Where did the 350 come from?
From pv=nRT where T =300,pressure is 10 and the moles are 4. I Find that V1=997.2
Seems too much. Please post the details of that calculation.
 
Sorry,I know it is T2-T1=-50 and here I find that T2=250 Kelvin.

The details pv=nRT , V=(4*8.31*300)/10=997.2 litres..
 
What are the units of your gas constant R?
 
R= 8.31 J *K−1 mol−1
 
SteamKing asked you about the units for the gas constant, because the units are wrong in your calculation of the initial volume.

Since it's best to stick to the units given in the question, use the gas constant
R = 0.08206 L.atm/K.mol

When you're putting numbers into an equation, always include the units and check what they give for the final answer. You can avoid a lot of errors doing this.
 
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