What is the final temp. of each liquid?

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To determine the final temperatures of liquid mercury and water after absorbing 15 kJ of heat, the formula q=mcΔt is essential. In this context, q represents the heat absorbed, m is the mass of the liquids, c is the specific heat capacity, and Δt is the change in temperature. It is crucial to ensure that the specific heat capacities used for both mercury and water are accurate and that the heat value of 15 kJ is converted to the appropriate units for consistency in calculations. The discussion highlights the importance of these factors in solving the problem and encourages participants to share their results for further analysis.
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You place 2 beakers at 25 degrees celsius on a hot plate.
Beaker A = 100.00 mL liquid Mercury
Beaker B = 100.00 mL liquid Water
Each absorb 15 KJ of heat.
What is the final temp. of each liquid?
 
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Have you attempted the problem? Keep in mind the general formula

q=mc\Delta t

where q is heat flow in joules (or kilojoules), m is mass in grams (or kilograms, if q was in kilojoules), c is the specific heat capacity in the appropriate units, and t the temperature in °C.
 
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.
 
BJN153 said:
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.

Show us your results.


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Are are you sure you are using the correct value of the specific heat capacities of each liquid. And if so, are you making sure you are converting your 15kJ to the properly corresponding energy unit?
 

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