What is the final temp. of each liquid?

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SUMMARY

The discussion focuses on calculating the final temperatures of 100.00 mL of liquid Mercury and liquid Water after each absorbs 15 kJ of heat. The relevant formula used is q=mcΔt, where q represents heat flow, m is mass, c is specific heat capacity, and Δt is the change in temperature. Participants emphasize the importance of using the correct specific heat capacities for Mercury and Water, as well as ensuring proper unit conversion for the heat energy from kilojoules to joules. The final temperatures can be determined by applying these principles accurately.

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  • Understanding of the formula q=mcΔt
  • Knowledge of specific heat capacities for Mercury and Water
  • Ability to convert energy units from kilojoules to joules
  • Basic principles of thermodynamics
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  • Research the specific heat capacity values for Mercury (0.14 J/g°C) and Water (4.18 J/g°C)
  • Learn about unit conversions between kilojoules and joules
  • Explore examples of heat transfer calculations in thermodynamics
  • Investigate the effects of different liquids on heat absorption and temperature changes
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Chemistry students, educators, and laboratory technicians who are involved in thermal calculations and heat transfer experiments.

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You place 2 beakers at 25 degrees celsius on a hot plate.
Beaker A = 100.00 mL liquid Mercury
Beaker B = 100.00 mL liquid Water
Each absorb 15 KJ of heat.
What is the final temp. of each liquid?
 
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Have you attempted the problem? Keep in mind the general formula

q=mc\Delta t

where q is heat flow in joules (or kilojoules), m is mass in grams (or kilograms, if q was in kilojoules), c is the specific heat capacity in the appropriate units, and t the temperature in °C.
 
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.
 
BJN153 said:
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.

Show us your results.


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Are are you sure you are using the correct value of the specific heat capacities of each liquid. And if so, are you making sure you are converting your 15kJ to the properly corresponding energy unit?
 

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