What is the final temp. of each liquid?

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Discussion Overview

The discussion revolves around a problem involving the final temperatures of two liquids, mercury and water, after each absorbs a specified amount of heat. The context includes theoretical and mathematical reasoning related to heat transfer and specific heat capacities.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a problem involving two beakers containing mercury and water, each initially at 25 degrees Celsius and absorbing 15 kJ of heat.
  • Another participant suggests using the formula q=mcΔt to solve the problem, where q represents heat flow, m is mass, c is specific heat capacity, and Δt is the change in temperature.
  • A participant expresses difficulty in identifying the error in their calculations and requests assistance in showing their results.
  • Another participant questions whether the correct specific heat capacities for mercury and water are being used and emphasizes the importance of converting the heat energy into the appropriate units.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants express differing levels of understanding and approach to solving the problem, with some seeking clarification on specific heat capacities and unit conversions.

Contextual Notes

Participants have not provided specific values for the specific heat capacities of mercury and water, nor have they detailed their calculations, leaving some assumptions and steps unresolved.

BJN153
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You place 2 beakers at 25 degrees celsius on a hot plate.
Beaker A = 100.00 mL liquid Mercury
Beaker B = 100.00 mL liquid Water
Each absorb 15 KJ of heat.
What is the final temp. of each liquid?
 
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Have you attempted the problem? Keep in mind the general formula

q=mc\Delta t

where q is heat flow in joules (or kilojoules), m is mass in grams (or kilograms, if q was in kilojoules), c is the specific heat capacity in the appropriate units, and t the temperature in °C.
 
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.
 
BJN153 said:
Thats what I've tried...but I can't seem to figure out what step I am going wrong in.

Show us your results.


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Are are you sure you are using the correct value of the specific heat capacities of each liquid. And if so, are you making sure you are converting your 15kJ to the properly corresponding energy unit?
 

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