What is the final velocity of the two balls in an elastic collision?

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SUMMARY

The final velocities of two balls in an elastic collision can be determined using the principles of conservation of momentum and kinetic energy. In this scenario, a 5 kg ball moving at 2 m/s collides with a stationary 7.5 kg ball. The correct final velocity of the 7.5 kg ball is 0.8 m/s, while the final velocity of the 5 kg ball is calculated to be 1.2 m/s after correcting the arithmetic error in the energy equation. The key mistake was in squaring the binomial during the energy calculation.

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Homework Statement



I can't believe I cannot get this! I am trying to help out my gf with this problem:

A 5 kg ball moving at 2 m/s to the right collides with a 7.5 kg stationary ball. If the collision is elastic, what are the final velocities of the 2 balls?

Homework Equations



Momentum is Conserved
KE is conserved


The Attempt at a Solution



Momentum

(m_1v_1)_o+(m_2v_2)_o = (m_1v_1)_f+(m_2v_2)_f

\Rightarrow (5)(2) + (7.5)(0) = 5v_{1f} + 7.5v_{2f}

v_{1f} = 2 - 1.5v_{2f} \qquad (1)

Energy

0.5(m_1v_1^2)_o+0.5(m_2v_2^2)_o = 0.5(m_1v_1^2)_f+0.5(m_2v_2^2)_f

\Rightarrow (5)(2)^2 = 5v_{1f}^2 + 7.5v_2f}^2

v_{1f} = \sqrt{4 - 1.5v_{2f}^2} \qquad (2)


From (1) and (2), we have

2 - 1.5v_{2f} = \sqrt{4 - 1.5v_{2f}^2}

\Rightarrow 4 - 3v_{2f} + 2.25v_{2f}^2 = 4 - 1.5v_{2f}

\Rightarrow 3.75v_{2f}^2 - 3v_{2f} = 0 = (3.75v_{2f} - 3)v_{2f}

\Rightarrow v_{2f} = 0.8 m/s

Which is incorrect.

What the heck am I missing? I feel like such an amateur right now! :redface:
 
Physics news on Phys.org
It's a simple arithmetic mistake... you didn't square the binomial correctly in...

(2 - 1.5v_2f) ^ 2

the cross term is -6v_2f not -3v_2f.
 
Elvex said:
It's a simple arithmetic mistake... you didn't square the binomial correctly in...

(2 - 1.5v_2f) ^ 2

the cross term is -6v_2f not -3v_2f.

Oh jeesh...thank you Elvex!
 

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