What is the formula for calculating the optical output power of an LED?

AI Thread Summary
The discussion focuses on calculating the optical output power of an LED for a science project, specifically using the formula Pout = N × Vres, where N is a linear factor that needs clarification. Participants suggest starting with a detailed LED datasheet to find necessary values and emphasize that N is not critical for comparing relative efficiencies between different light sources, as it cancels out in ratio calculations. The importance of measuring the distance from the photocell to the light source is questioned, with guidance provided on how to approach the experiment without needing to determine N. Overall, the conversation highlights the relationship between input and output power in assessing LED efficiency, while suggesting practical steps for experimentation.
daPoseidonGuy
Messages
2
Reaction score
0
Hi, i was doing a science project on LEDs, and i needed to calculate optical output power versus input electrical power to find relative wall plug efficiency.
This is the only good formula i found
Optical output power of LED (watts) =Nlinearfactor × Voltage drop across resistor (volts)
Pout = N × Vres
What is N exactly? I do not know how to calculate optical output power as I don't know what help is. Id appreciate help a lot, thanks.
 
Engineering news on Phys.org
daPoseidonGuy said:
Hi, i was doing a science project on LEDs, and i needed to calculate optical output power versus input electrical power to find relative wall plug efficiency.
This is the only good formula i found
Optical output power of LED (watts) =Nlinearfactor × Voltage drop across resistor (volts)
Pout = N × Vres
What is N exactly? I do not know how to calculate optical output power as I don't know what help is. Id appreciate help a lot, thanks.
Welcome to the PF.

I'd start with a good datasheet for a typical LED. There should be curves for optical output versus current. The old Hewlett Packard LED datasheets were especially complete. Can you post a link to a detailed LED datasheet that has some of the numbers you are looking for? :smile:
 
Heres a more complete post:
Hi, i was doing a science project on LEDs, and i needed to calculate optical output power versus input electrical power to find relative wall plug efficiency.
This is the only good formula i found
Optical output power of LED (watts) =Nlinearfactor × Voltage drop across resistor (volts)
Pout = N × Vres
What is N exactly? I do not know how to calculate optical output power as I don't know what help is. Id appreciate help a lot, thanks.
All the values I have are experimental. I am trying to calculate the relative wall plug efficiency of an LED. here's my data right now.
I do not have a data sheet and the steps I am following at this point are somewhat modeled of those shown here:
http://www.sciencebuddies.org/science-fair-projects/project_ideas/Energy_p003.shtml#procedure
in the testing and data collection section.

Voltage across resistor (V) ± .01 = 2.49

Distance from photocell to light (cm) ± .05 = 4.00

Voltage across light (V) ± .01 = 5.75

Current intensity (mA) ± .01 = 360
If N is just something I have to leave as a variable, then what is the point of measuring the distance between the photocell and the light bulb? In the experiment I moved the breadboard closer or further to get 2.5v across the resistor, as that's what I understood from the procedure. Was I supposed to do that? What do I do with the value for the distance between the photocell and light bulb?
 
Last edited:
that experiment doesn't give a value for N, only compares N for LED vs incandescent lamp.
Try this datasheet..http://www.vishay.com/docs/81011/tsal6400.pdf

and see if this helps you estimate N for that particular LED

upload_2015-12-27_14-55-57.png


good opportunity to learn about steradians .
 
  • Like
Likes berkeman
From the project link:
N cannot be determined easily, as it depends on the light emission vs. angle for each source.

The project is
1. Build a light detector. Don't worry about the detector's N since we assume it is constant across all emitters.
2. Try different sources and calculate input power vs output power (efficiency) using the detector.

You don't really need to know N to determine relative efficiency of two different sources since they assume the detector's N is the same for all sources. They also assume the detector is 100% efficient, that is, it is detecting all the light from each source (or a similar fraction).
"Since you are not collecting all of the light at the light-to-voltage converter (some of the light goes off to the side), the calculation is relative."

When you take the ratio of the two sources, the N will cancel out.

In other words, you are sort of measuring light output in units of N. N goes away when you take ratios of two measurements.

If you want to measure the absolute power of a single emitter, you need to somehow calibrate the detector, which requires a known source, etc.
 
  • Like
Likes berkeman and billy_joule
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
Thread 'Weird near-field phenomenon I get in my EM simulation'
I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
Back
Top