What is the frequency of a photon of energy 58eV?

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SUMMARY

The frequency of a photon with an energy of 58 eV can be calculated using the equation E = hF, where E is energy, h is Planck's constant (6.63 x 10-34 J·s), and F is frequency. To convert electron volts to joules, use the conversion factor 1 eV = 1.602 x 10-19 J. The correct calculation yields a frequency of approximately 1.39 x 1015 Hz, not 8.75 x 1034 Hz as initially attempted.

PREREQUISITES
  • Understanding of photon energy and frequency relationship
  • Familiarity with Planck's constant
  • Knowledge of unit conversion from electron volts to joules
  • Basic grasp of the MKS (meter-kilogram-second) system
NEXT STEPS
  • Study the concept of photon energy and frequency using E = hF
  • Learn about unit conversions, specifically between electron volts and joules
  • Explore the implications of Planck's constant in quantum mechanics
  • Investigate the properties of electromagnetic radiation and its spectrum
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Homework Statement



What is the frequency of a photon of energy 58eV?

Homework Equations



E=hF

where H is Planck's constant, 6.63x10^-34



The Attempt at a Solution



58/ (6.63x10^-34) = 8.75e34

that is not correct.

Do i have the energy eV into a certain unit?
 
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Hint: 1eV = 1.602E-19 J
 
When in doubt, put everything in units of MKS (meters, seconds, and kg).

MKS energy unit is the Joule = kg * m^2 / s^2
 

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