I What is the gas composition in a tank with a SF6 leak?

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A leak was discovered in a SF6 gas high-voltage circuit breaker, leading to uncertainty about the gas composition in the tank. The discussion revolves around calculating the percentage of SF6 and air in the tank after adding SF6 gas to a pressure of 0.2 bar above atmospheric pressure. The calculations consider constant temperature and volume, with the total pressure being the sum of atmospheric pressure and the added SF6 pressure. The proposed formula for determining the percentage of SF6 is confirmed as correct, although there is a concern that SF6 may accumulate at the bottom of the tank due to its density. Understanding the gas composition is crucial for safety and operational integrity.
Graaf van Vlaanderen
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We discovered a leak in a SF6 gas HV circuit breaker. Since we don't know when the leak occurred due to temperature changes I assume there is only air left in the tank.
Here is my question. Suppose I have a tank with a fixed volume filled with air at the same pressure as the atmospheric pressure. When we add SF6 gas up to 0.2bar over pressure, what would then be the percentage of each gas (air and SF6) in the tank?
 
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You have three numbers; what do you calculate from them?
 
Well, I consider T and V constant, hence ntot = n(air) + n(SF6) => ptot = p(atm) + p(SF6)
Hence %SF6 = (0.2/1.2)*100. Not sure this is correct.
 
You got it.
 
But I'd expect all the SF6 will pool on the bottom of the tank.
 
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