I What Is the Geometrical Interpretation of Bounded Curves?

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A curve in R^3 is defined by its curvature and torsion, which are functions of the arc-length parameter. The discussion highlights the challenge of restoring curve features from these functions, as the Frenet-Serret equations are not generally integrable. A key property of interest is boundedness, defined by the boundedness of the radius-vector. If the ratio of curvature to torsion is monotone and approaches zero as the arc-length increases, the curve is unbounded. The conversation invites further exploration of the geometrical interpretation of these concepts and seeks clarification on the meaning of bounded curves.
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It is well known that a curve in ##\mathbb{R}^3## is uniquely (up to a position in the space) defined by its curvature ##\kappa(s)## and torsion ##\tau(s)##, here ##s## is the arc-length parameter. We will consider ##\kappa(s),\tau(s)\in C[0,\infty)##

Thus a natural problem arises: to restore features of the curve from given functions ##\kappa(s),\tau(s)##. This is not a simple problem: the Frenet-Serret equations are not in general integrable explicitly.A simplest property of the curve is boundedness. We shall say that a curve is bounded iff its radius-vector is bounded: $$\sup_{s\ge 0}|\boldsymbol r(s)|<\infty.$$

For example, if a function ##\kappa(s)/\tau(s)## is monotone and
$$\lim_{s\to\infty}\frac{\kappa(s)}{s\cdot\tau(s)}=0$$ then the curve is unbounded. This is an almost trivial fact, it follows from some another almost trivial theorem, for details see http://www.ma.utexas.edu/mp_arc/c/16/16-63.pdf

The comments are welcome. Particularly is there a geometrical interpretation of brought above proposition
 
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wrobel said:
It is well known that a curve in ##\mathbb{R}^3## is uniquely (up to a position in the space) defined by its curvature ##\kappa(s)## and torsion ##\tau(s)##, here ##s## is the arc-length parameter. We will consider ##\kappa(s),\tau(s)\in C[0,\infty)##

Thus a natural problem arises: to restore features of the curve from given functions ##\kappa(s),\tau(s)##. This is not a simple problem: the Frenet-Serret equations are not in general integrable explicitly.A simplest property of the curve is boundedness. We shall say that a curve is bounded iff its radius-vector is bounded: $$\sup_{s\ge 0}|\boldsymbol r(s)|<\infty.$$

For example, if a function ##\kappa(s)/\tau(s)## is monotone and
$$\lim_{s\to\infty}\frac{\kappa(s)}{s\cdot\tau(s)}=0$$ then the curve is unbounded. This is an almost trivial fact, it follows from some another almost trivial theorem, for details see http://www.ma.utexas.edu/mp_arc/c/16/16-63.pdf

The comments are welcome. Particularly is there a geometrical interpretation of brought above proposition
I find it amazing. But will you explain me the restore features of curve. Actually I am going to read about curves in detail but I need little guidance. Can you name some of the books which I can buy.
 
I was saying that why you have used word bounded curves. Will you tell me its precise meaning.
 
Be more specific what you are saying
 
shina said:
was saying that why you have used word bounded curves. Will you tell me its precise meaning.
I have already done that
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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