Chemistry What is the identity of element M in the reaction with fluorine?

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The discussion revolves around identifying element M in a reaction with fluorine, where 0.6 moles of M produce 46.8 grams of MF2. It is established that each mole of MF2 contains two moles of fluorine, leading to the conclusion that 0.6 moles of MF2 contains 1.2 moles of fluorine. The mass of fluorine in the reaction is calculated to be 22.8 grams, allowing for the determination of the mass of element M as 24 grams. This results in a molar mass of 40 g/mol for element M, which corresponds to calcium. The identity of element M is confirmed to be calcium.
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Homework Statement


a sample of 0.6 moles of a metal M reacts completely with excess of flourine to form 46.8 gms of MF2.
a)how many moles of F are present in the sample of MF2 that forms?
b)which element is represented by the symbol M?


Homework Equations


NO. OF MOLES=given mass/molar mass


The Attempt at a Solution


molesof element M:moles of compound formed MF2
1 : 1
0.6 : 0.6
1 mole of MF2 contains 2 moles of F
0.6 MOLES WOULD CONTAIN=0.6*2=1.2

now i dnt no how can i find which element it is
 
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Think how you can calculate its molar mass from the information given.

--
methods
 
i tried my best i m nt getting which formula to use
 
A little more: how much MF2 do you have at the end of your reaction?
 
Tedjn said:
A little more: how much MF2 do you have at the end of your reaction?
total MF2=46.8GMS
atomic mass of flourine=19 g/mol
mass=moles*atomic mass
=0.6*19
= 22.8gms
hence
mass of element M=46.8-22.8
=24gms
molar mass of element M=mass of M/moles of M
=24GMS/0.6
=40 g/mol
atomic mass of element M=40g/mol
this is atomic mass of calcium
 
so the element is calcium

thnx a lot for ur help
 
Wasn't that hard :wink
 

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