What is the Initial Acceleration of a Charged Particle in an Electric Field?

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To find the initial acceleration of a charged particle in an electric field, start by applying Coulomb's law to calculate the force between the two charged particles. The force is determined using the formula F = k (Q1)(Q2) / r^2, where k is Coulomb's constant, Q1 and Q2 are the charges, and r is the distance between them. The calculated force is approximately -7.39 x 10^13 N. To find acceleration, use Newton's second law (F = ma), ensuring to convert the mass from grams to kilograms for consistent units. Proper unit conversion and application of the formulas will yield the correct acceleration in m/s^2.
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im stuck on this question if any1 could help i'd appreciate it. A particle of mass 30 g and charge 26 uC is released ffrom rest when it is 59 cm from a second particle of charge -11 uC. The question ask for the initial acceleration of the 30 g particle.
 
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To start with...

Try working out the forces being exerted by the particles.
 
What force acts on the particle? (Hint: Consider Coulomb's law)
 
so i work out the forces using coulombs law, but then how do u find acceleration in m/s?
 
Use Newton's 2nd law. (Acceleration has units of m/s^2, not m/s.)
 
heres what i got can u tell me if its on the right track

F = k (Q1) (Q2) / r^2

F = (9.0 x 10^9) (26uC) (-11uC) / (0.59m)^2


= -7.39 x 10^13 N
 
Last edited:
Realize that \mu \mbox{C} means micro-Coulombs: 1 \mu \mbox{C} = 10^{-6} \mbox{C}.
 
when dividing by the mass do i have to change grams to kg?
 
Think of the units that make up a Newton and make sure you use the same
 
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thank u guys for ur help
 
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