What is the Integral of 3x (sinx/cos^4x) dx?

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can anybody help me with this problem
Evaluate :
integral 3x (sinx/cos^4x) dx
 
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Is it \int \frac{3x\sin x}{\cos^{4} x}?

Rewrite it as 3\int x\tan x\ sec^{3} x and use integration by parts
 
Last edited:
i know the equation for intergration by parts is
intergral u dv = uv -intergral v du

can u tell me which variable is which?...u, du, v, dv=?...there seems to have 3 different variable.
 
Let u = x and dv = \ tan x \sec^{3} x. You will then need to use integration by parts on dv to get v.
 
Last edited:
I'm sure courtrigrad meant u= x and dv= tan x sec^3 xdx (with out the "x" in dv).
 
yep, thanks catching that :smile:
 

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