What is the intensity of the transmitted light?

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The discussion revolves around calculating the intensity of transmitted light through two polarizers that are misaligned by 30 degrees. The initial light intensity is given as 3.86 W/m², and it is polarized halfway between the two filters. The correct application of Malus' Law involves using the formula I = I0 * cos²(theta), rather than I = I0 * cos(theta). After applying the correct formula, the intensity of the transmitted light can be accurately determined. The conversation emphasizes the importance of using the squared cosine in the calculation for precise results.
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Homework Statement


Two polarizers are out of alignment by 30°. If light of intensity 3.86 W/m2 and initially polarized halfway between the polarizing angles of the two filters passes through the two filters, what is the intensity of the transmitted light?


The Attempt at a Solution



Use Malus' law:

I = I0 * cos(theta)
which gives me 3.34 W/m2

but it's not right... any hints?
should i divide it by 2 since it says that it is polarized halfway between ?
 
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You have the wrong expression for Malus' law.
 
i forgot square

I = I0 * cos(theta)^2 other than that it's right
 
So how would you go about solving this now that you have the correct form of Malus' Law?
 

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