What is the key to solving this two and three force members problem?

[Lmck33]

Homework Statement

Hi, I've been looking over this problem and I can't manage to find a suitable approach to such a question :S maybe you could help me out. The structure can be seen in the given image.

As shown, a load of magnitude is applied to a structure. Assuming that all members are weightless and that ABEF and BCD are rigid bodies, find the magnitudes of the reactions at D and G needed to maintain the structure in equilibrium.

Assume the following values: a = 4.50m , b = 3.00m , and P = 110N .

Homework Equations

Equilibrium equations..

The Attempt at a Solution

No attemps..

 

[Lmck33]

thanks for the overwhelming help :D i managed to work it out by myself.

 

[engineerman01]

I know you did this problem long ago, but if you still understand how to do it, could you please explain? I am very lost

 

[Ady1219]

where could i find how to this problem?!

 

[PhanthomJay]

where could i find how to this problem?!

Hi, Ady1219, welcome to Physics Forums!
Looks like lmck33 couldn't wait a day for the help, so he may still be a bit heated. Hint: Can you identify a 2 force member in this problem? There are two of them. A 2-force member is one in which forces are applied at the ends of the member only, with no forces in between, and as a result, the 2 forces on these members must be equal and opposite and point toward each other from one end to the other, from equilibrium considerations.

 

[oyala]

Hi guys

I really need help with that Question, I really don't how to find the reaction force acting D and G. I have Identified all the 2 and 3 force members so far but still haven't got enought skill to find the solution.

anyone keen to explain to me will be great !.

 

[pongo38]

The key to this problem is to understand the difference between the hinge at E and the hinge at F. Whereas ABEF is a bar with various moments in it, especially at E because it is continuous there, F is different. What do you know about the bending moment at F? How does that help you find the reaction at G?