What is the Lagrange Point Between Jupiter and the Sun for a Space Probe?

AI Thread Summary
The discussion centers on calculating the Lagrange Point between Jupiter and the Sun for a space probe, focusing on the balance of gravitational forces. A participant initially calculated a distance of 2.4e7 km but faced issues with accuracy. Clarifications were made regarding the correct distance from the Sun to Jupiter, which is approximately 7.78e11 meters, not 2.78e-11 meters. The conversation emphasizes the importance of using the correct average distance and considering variations when Jupiter is at different positions in its orbit. Accurate calculations depend on these factors to determine the precise location for the space probe.
Forceflow
Messages
30
Reaction score
0
How far from Jupiter must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances Jupiter's pull?

i know that i need to use m1/r2=m2/((2.78e-11)-r)squared
but my answers keep coming out wrong. For an answer, i got 2.4e7 km
 
Physics news on Phys.org
can someone help me?
 
Forceflow said:
How far from Jupiter must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances Jupiter's pull?

i know that i need to use m1/r2=m2/((2.78e-11)-r)squared
but my answers keep coming out wrong. For an answer, i got 2.4e7 km
If 2.78e11 is the distance from the sun to Jupiter and m1 and m2 are the masses of the sun and Jupiter, you should be OK. Do you have the right units? Did you expand the square in the denominator correctly? Is that a negative exponent e-11? Surely it should not be.
 
Last edited:
yes, I'm sure i have the units correct. Its possible that the mean distance to the sun from Jupiter is 778e6.
 
Forceflow said:
yes, I'm sure i have the units correct. Its possible that the mean distance to the sun from Jupiter is 778e6.
I just looked it up and averaged the max and min and got 779e6Km.

http://www.windows.ucar.edu/tour/link=/jupiter/statistics.html

So I guess what you meant the first time was 7.78e11m rather tha 2.78e-11m. With this distance you should be getting a reasonable answer if the question is looking for the average. If its asking for the distance when Jupiter is foarthest from the sun, or perhaps closest, then obviouly the average will not do.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top