What is the limit of sin|x|/x as x approaches 0?

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Homework Statement



I want to find the limit:

\lim_{x\to 0}\frac{sin|x|}{x}


The Attempt at a Solution



I know that the answer must be "limit doesn't exist" but I don't know how to arrive at that answer. I know that \lim_{x\to 0}\frac{sinx}{x}=1 but apparently it's a very different situation. Can anyone show me how to find this limit?
 
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Look at the two one-sided limits, and see if they are the same or different.
 
Mark44 said:
Look at the two one-sided limits, and see if they are the same or different.

What are the two one sided limits? That's what I don't get!
 
lim x -->0+
lim x -->0-

For the first, |x| = x
For the second, |x| = -x
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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