erik05
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Hello all. I missed a class in calculus so I didn't get the notes on this so if anyone could explain this question for me, it would be much appreciated.
\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?
Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.
\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?
Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.