What is the Limit of the Tangent Function as x Approaches 0?

AI Thread Summary
The limit of the tangent function as x approaches 0 is discussed, specifically the expression lim(x → 0) (tan x)/(4x). Participants clarify that using l'Hôpital's rule is not permitted for this problem and suggest starting from the known limit lim(x → 0) (sin x)/x = 1. The discussion leads to recognizing that the limit can be simplified to 1/4 by using the relationship between sine and tangent. Ultimately, the solution is confirmed as lim(x → 0) (tan x)/(4x) = 1/4. The conversation highlights the importance of foundational calculus concepts in solving limits.
erik05
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Hello all. I missed a class in calculus so I didn't get the notes on this so if anyone could explain this question for me, it would be much appreciated.

\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?

Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.
 
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You can't do that!



Use l'hopitals rule.

\lim_{x \rightarrow 0} \frac {tanx}{4x} =\lim_{x \rightarrow 0} \frac {secxtanx}{4}
 
Sorry, I haven't learned l'hopitals rule yet and we're not suppose to use it for these questions.
 
expand tanx in taylor series, and do what you should do...
 
This is going to sound really pathetic but no, we haven't the taylor series either.
 
do you know the fact that
\lim_{x \rightarrow 0} \frac {sinx}{x} =1
if yes, you should start from here
 
I think Taylor series is taught way after l'Hôpital's rule,don't u think so?:rolleyes:

Daniel.
 
vincentchan said:
do you know the fact that
\lim_{x \rightarrow 0} \frac {sinx}{x} =1
if yes, you should start from here

That I do know.
 
What about "tangent's" definition...?And the limit of cosine as its argument goes to 0 ?

Daniel.
 
  • #10
erik05 said:
Hello all. I missed a class in calculus so I didn't get the notes on this so if anyone could explain this question for me, it would be much appreciated.

\lim_{x \rightarrow 0} \frac {tanx}{4x}
= \frac {sinx}{cos4x} ?

Not really too sure if I manipulated the equation right. Any hints for the next step? Thanks.

= 1/4*(sin[x]/x)*(sec[x])
 
  • #11
Ah...I got it. Thanks all.
 
  • #12
Limit Laminate...


Solution:
\boxed{\lim_{x \rightarrow 0} \frac {\tan x}{4x} = \frac{1}{4}}
[/color]
 
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  • #13
How fancy that \boxed{...},too bad u don't know "\tan"...:rolleyes:

Daniel.

P.S.BTW,I've searched Mathworld and A & S,couln't find this tanx function... :bugeye:

P.P.S.Neither sinx,nor secxtanx,but i found \mbox{sinc}\ x...

P.P.P.S.You edited... :wink:
 
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