What is the Magnitude of Deceleration of a Meteorite Striking a Car?

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To determine the magnitude of deceleration of a meteorite striking a car, the scenario involves a 27 lb meteorite penetrating 27 cm into the trunk at an initial speed of 520 m/s. The discussion highlights the use of kinematic equations to solve for deceleration without needing time. The relevant equation relates distance, initial velocity, final velocity, and acceleration, allowing for the calculation of deceleration directly. Participants emphasize the importance of understanding the variables involved, such as distance (s), initial velocity (u), and final velocity (v). The solution can be reached by selecting the appropriate kinematic equation that excludes time.
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Homework Statement


A 27 lb meteorite struck a car, leaving a 27 cm deep in the trunk. If the meteorite stuck the car with a 520 m/s what was the magnitude of deceleration assuming it to be constant


Homework Equations


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The Attempt at a Solution


I have to be honest I have no clue whatsoever could someone please direct me on how to just attack this question because I have no idea where to begin
 
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Use the simultaneous equations s=vt-\frac{1}{2}at^2 and s=ut+\frac{1}{2}at^2.
 
Sorry if this is a stupid response but I just started taking Physics this week and have no idea what those letters stand for.
 
Well, "s" is the distance, which would be the distance of penetration in this case, "a" is the acceleration, "t" is the time, "v" is the final velocity, and "u" is the initial velocity.
 
So s = 27 cm, a = what your looking for v = 0 m/s u = 520 m/s what's the time here?
 
if you're not given time, you will need to choose a diff eqn or you can plug 1 eqn into another to get rid of time.
 
If you look at your kinematic equations, can you find one that relates all the things you have there without time? You don't need time to solve this problem. You can do it with one equation.
 
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