What is the Magnitude of Force P to Keep a Block Stationary Against a Wall?

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The discussion focuses on calculating the magnitude of force P required to keep a 3.00 kg block stationary against a wall at a 50.0-degree angle. The coefficient of static friction between the block and the wall is 0.250. The analysis involves resolving forces in both the horizontal and vertical directions, establishing that the normal force N must balance the horizontal component of the applied force P. Additionally, the friction force acting downward is defined as f = μN, where μ is the coefficient of static friction.

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Wild ownz al
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A block of mass 3.00kg is pushed up against a wall by a force of P that makes a 50.0 degree angle with the horizontal (REFER TO PICTURE). The coefficient of static friction between the block and the wall is 0.250. Determine the possible values for the magnitude of P that allow the block to remain stationary.
 

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You have an applied force which has a component in the horizontal direction. You also have a normal force directed in the opposite direction. (Let's say that N is in the negative x direction and the component of the applied force is in the +x.) The sum of these two forces must be 0 N as there is no motion in this direction. This gives you N in terms of the applied force. Thus [math]\sum F _x = -N + F~cos(50) = 0[/math].

What can you say about the vertical (y) direction? Do the same thing. A lot of stuff will cancel out.

By the way, you missed a force on your diagram. There is a friction force acting downward of magnitude [math]f = \mu N[/math].)

See what you can do with this.

-Dan
 

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