What is the magnitude of the impulse

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    Impulse Magnitude
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To find the magnitude of the impulse on the wall from the ball, first calculate the initial kinetic energy using the formula KE = 1/2 mv^2, which results in 4.08 J for the incoming ball. Since the ball rebounds with only 50% of its initial kinetic energy, the kinetic energy after rebounding is 2.04 J. The change in momentum (ΔP) can be determined by finding the momentum before and after the collision, leading to an impulse (I) of 1.3 N s. This calculation confirms that the impulse experienced by the wall is indeed 1.3 N s. Understanding these principles is crucial for solving similar physics problems.
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Homework Statement


a ball having a mass of 150 g strikes a wall with a speed of 5.2 m/s and rebounds with only 50% of its initial kinetic energy. what is the magnitude of the impulse on the wall from the ball?


Homework Equations


I=Ft
I=ΔP
KE= 1/2 m v^2


The Attempt at a Solution


the answer is 1.3 N s but i don't know how to get there.
 
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What was its kinetic energy before hitting the wall? What was its kinetic energy after rebounding?

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