What is the mass and lifetime of the φ meson?

Darkkk
Messages
5
Reaction score
0
An electron and a positron are collided head on such that all their energy is used to produce a φmeson. The number of observed φ mesons is found to be inversely proportional to (E−E0)+Γ2/4. where E is the total centre of mass collision energy, E0=1019 MeV and Γ=4.26MeV

What is the mass and lifetime of the
φmeson?


Hi feeling rather frustrated with this question, not sure where to start really! any advice would be most appreciated! thanks
 
Physics news on Phys.org
That expression isn't correct. The units don't work out.

Hint: Look up the Breit-Wigner distribution.
 
OK so this is how far I got with this one...

found the mean lifetime using

\tau=(h/2\pi)/\Gamma

This gave me a value of 1.5x10-22

Is that correct?

also still stumped on how to find the mass...
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top