riseofphoenix
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The answer to this is up (d).
But why?
Is it because centripetal acceleration is pointing to the center of the pivot?
I believe this is correct.Is it because centripetal acceleration is pointing to the center of the pivot?
cbasst said:I believe this is correct.
In regards to how you should go about finding the gravitational acceleration you would feel on Jupiter, keep in mind that you are supposed to be finding acceleration. You look like you were solving for the force Jupiter will exert on an object, not the acceleration of gravity on Jupiter. This is a problem because the force that Jupiter will exert on an object depends on the mass of the object. It is true that
Fg = G Mm/r2
What else is Fg equal to? Could you use that relationship to find the acceleration on Jupiter?
Chestermiller said:Why did you insert gJupiter in the right hand side of the equation? G is a universal constant, and not related specifically to Jupiter. And where did the 9.81 come from? We are talking about Jupiter, not earth. In you most recent post, m is equal to m2, and g is what you are solving for; m2 is the mass of Jupiter.
riseofphoenix said:So,
mg = (6.67 x 10-11)m1(1.9 x 1027)/71.4922
(1.9 x 1027)g = (6.67 x 10-11)m1(1.9 x 1027)/71.4922
What about m1??
m = m2 = your mass
Chestermiller said:I'm sorry. I made a typo in my previous reply. Please excuse me. It should have read:
m = m2 = your mass
m1 = mass of Jupiter